Mathematical Problem by Bhaskaracharya

Whilst making love a necklace broke.
A row of pearls mislaid.
One sixth fell to the floor.
One fifth upon the bed.
The young woman saved one third of them.
One tenth were caught by her lover.
If six pearls remained upon the string
How many pearls were there altogether?



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3 comments:

Sash said...

can you please post the answer for this question.

David McKelvie said...

Let the total number of pearls be x. Therefore the number of pearls is a sixth of x plus a fifth of x plus a third of x plus a tenth of x (this all boils down to four fifths of x) plus six left over.

So, x = 4/5 x + 6

i.e. x - 4/5 x = 6

Which means x = 30.

David McKelvie said...

Let the total number of pearls be x. Therefore the number of pearls is a sixth of x plus a fifth of x plus a third of x plus a tenth of x (this all boils down to four fifths of x) plus six left over.

So, x = 4/5 x + 6

i.e. x - 4/5 x = 6

Which means x = 30.